MCQ
If $\tan A - \tan B = x$ and $\cot B - \cot A = y,$ then $\cot (A - B) = $
  • A
    $\frac{1}{x} + y$
  • B
    $\frac{1}{{xy}}$
  • C
    $\frac{1}{x} - \frac{1}{y}$
  • $\frac{1}{x} + \frac{1}{y}$

Answer

Correct option: D.
$\frac{1}{x} + \frac{1}{y}$
d
(d) $\cot \,(A - B) = \frac{1}{{\tan \,(A - B)}} $

$= \frac{{1 + \tan A\,\,\tan B}}{{\tan A - \tan B}}$

$ = \frac{1}{{\tan A - \tan B}} + \frac{{\tan A\,\,\tan B}}{{\tan A - \tan B}} $

$= \frac{1}{x} + \frac{1}{y}$.

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