MCQ
If $\tan A - \tan B = x$ and $\cot B - \cot A = y,$ then $\cot (A - B) = $
- A$\frac{1}{x} + y$
- B$\frac{1}{{xy}}$
- C$\frac{1}{x} - \frac{1}{y}$
- ✓$\frac{1}{x} + \frac{1}{y}$
$= \frac{{1 + \tan A\,\,\tan B}}{{\tan A - \tan B}}$
$ = \frac{1}{{\tan A - \tan B}} + \frac{{\tan A\,\,\tan B}}{{\tan A - \tan B}} $
$= \frac{1}{x} + \frac{1}{y}$.
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