MCQ
If $\tan A -\tan B =x$ and $\cot B -\cot A =y$, then $\cot (A-B)=$
- A$\frac{1}{x}+y$
- B$\frac{1}{x y}$
- C$\frac{1}{x}-\frac{1}{y}$
- ✓$\frac{1}{x}+\frac{1}{y}$
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