MCQ
If $\tan A=\cot B$, then:
- A$\mathrm{A}-\mathrm{B}=90^{\circ}$
- B$\mathrm{A}=\mathrm{B}=90^{\circ}$
- C$\mathrm{A}+\mathrm{B}=90^{\circ}$
- D$\mathrm{B}-\mathrm{A}=90^{\circ}$
✓
Answer
Self
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