MCQ
If $\tan \frac{A}{2}=\frac{3}{2}$, then $\frac{1+\cos A}{1-\cos A}=$
  • A
    -5
  • B
    5
  • C
    $\frac{9}{4}$
  • $\frac{4}{9}$

Answer

Correct option: D.
$\frac{4}{9}$
(D)
Given that, $\tan \frac{ A }{2}=\frac{3}{2}$
$\therefore \frac{1+\cos A }{1-\cos A }=\cot ^2 \frac{A}{2}$
$\frac{1+\cos \theta}{1-\cos \theta}=\cot ^2 \frac{\theta}{2}$, where $\theta \neq 2 n \pi$
$=\left(\frac{2}{3}\right)^2=\frac{4}{9}$

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