MCQ
If $tanA + cotA = 4$, then $tan^4A + cot^4A$ is equal to
- A$110$
- B$191$
- C$80$
- ✓$194$
$\Rightarrow \quad \tan ^{2} A+\cot ^{2} A+2=16$
$\Rightarrow \quad \tan ^{2} A+\cot ^{2} A=14$
$\Rightarrow \quad\left(\tan ^{2} A+\cot ^{2} A\right)^{2}=196$
$\Rightarrow \quad \tan ^{4} A+\cot ^{4} A+2=196$
$\Rightarrow \quad \tan ^{4} A+\cot ^{4} A=194$
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