MCQ
If $\text{A} = \begin{bmatrix} 2 &\text{amp; } 3\\ 6 &\text{amp; x} \end{bmatrix}, \text{B} = \begin{bmatrix} 2 &\text{amp; 3}\\ \text{p} &\text{amp; }2 \end{bmatrix}$ and $\text{A} = \text{B}, $ then$\text{p}$ and $ \text{x} $ are:
  • A
    p = 6, x = 4
  • B
    p = 3, x = 4
  • C
    p = 4, x = 3
  • p = 6, x = 2

Answer

Correct option: D.
p = 6, x = 2
Weve, two matrices will be same, if the given two matrices have same number of rows and columns and each elements of that two matrices are same.

Now equating the given two matrices we get, 6 = p and x = 2.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If the system of linear equations $x - 2y + kz = 1$ ; $2x + y + z = 2$ ;  $3x - y - kz = 3$ Has a solution $(x, y, z) \ne 0$, then $(x, y)$ lies on the straight line whose equation is
Which of the following is a homogeneous differential equation?
Objective of LPP is:
A bag ‘$A$’ contains $2$ white and $3$ red balls and bag ‘$B$’ contains $4$ white and $5$ red balls. One ball is drawn at random from a randomly chosen bag and is found to be red. The probability that it was drawn from bag $‘B’$ was
What is the value of $ \cos (2 \cos^{-1} 0.8)\cos(2\cos−10.8)?$
The function $\text{f(x)}=\begin{cases}\frac{\sin3\text{x}}{\text{x}},&\text{x}\ne0\\\frac{\text{k}}{2},&\text{x}=0\end{cases}$ is continuous at $x = 0,$ then $k =$
$\int {\left( {\sin \left( {101x} \right).{{\sin }^{99}}x} \right)} dx = \frac{{\sin \left( {100x} \right){{\left( {\sin x} \right)}^\lambda }}}{\mu } + C$ where $C$ is constant of integration then $\frac{\lambda }{\mu }$ is equal to
If  $2\int_0^1 {{{\tan }^{ - 1}}}\,xdx = \int_0^1 {{{\cot }^{ - 1}}}\,(1 - x + {x^2})dx,$ then $\int_0^1 {{{\tan }^{ - 1}}}\, (1 - x + {x^2})dx$  is equal to 
If  $ A, B, C, D$  are any four points in space, then $|\overrightarrow {AB} \times \overrightarrow {CD} + \overrightarrow {BC} \times \overrightarrow {AD} + \overrightarrow {CA} \times \overrightarrow {BD} |$ is equal to           (where $Delta$ denotes the area of $\Delta ABC$)
if $\text{y}=\text{e}^{{\tan}\text{x}},$ then $(\cos^2\text{x})\text{y}_2=$