Question
If $\text{A}=\begin{bmatrix} 3 & 1 \\ 2 & -3 \end{bmatrix},$ then find |adj A|.

Answer

$\text{A}=\begin{bmatrix} 3 & 1 \\ 2 & -3 \end{bmatrix}$Now, $|adj A| = |A|^{n-1} .....(i)$
Now, |$A| = -9 - 2 = -11$
So, $|adj A| = (-11)^{2-1}$
$= (-11)^1$
$= -11$
Hence, $|adj A| = -11$

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