Question
If $\text{A}=\begin{bmatrix}0&-1&2\\4&3&-4\end{bmatrix}$ and $\text{B}=\begin{bmatrix}4&0\\1&3\\2&6\end{bmatrix},$ then verify that $(\text{A}')'=\text{A}.$

Answer

We have, $\text{A}=\begin{bmatrix}0&-1&2\\4&3&-4\end{bmatrix}$ and $\text{B}=\begin{bmatrix}4&0\\1&3\\2&6\end{bmatrix}$We have to verify that, $(\text{A}')'=\text{A}$
$\therefore\ \text{A}'=\begin{bmatrix}0&4\\-1&3\\2&-4\end{bmatrix}$
and $(\text{A}')'=\begin{bmatrix}0&-1&2\\4&3&-4\end{bmatrix}=\text{A}$ Hence Proved.

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