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Trigonometric Ratios Of Compound Angles — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsTrigonometric Ratios Of Compound Angles3 Marks
Question
If $\text{a}\cos2\text{x}+\text{b}\sin2\text{x}=\text{c}$ has $\alpha$ and $\beta$ as its roots, then prove that,
$\tan\alpha\tan\beta=\frac{\text{c}-\text{a}}{\text{c+a}}$
✓

Answer

$\cos2\theta=\frac{1-\tan^2\theta}{1+\tan^2\theta}$
$\sin^2\theta=\frac{2\tan\theta}{1+\tan^2\theta}$
substitute these valuse in the given equation, it reduces to
$\text{a}(1-\tan^2)+\text{b}(2\tan\theta)=\text{c}(1+\tan^2\theta)$
$(\text{c+a})\tan^2\theta+2\text{b}\tan\theta+\text{C-a}=0$
As $\alpha$ and $\beta$ are roots
Product of roots, $\tan\alpha\tan\beta=\frac{\text{c-a}}{\text{c+a}}$

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