MCQ
If $ \text{A}+\displaystyle \begin{vmatrix} 4 &\text{amp; } 2 \\ 1 &\text{amp; } 3 \end{vmatrix}=\displaystyle \begin{vmatrix} 6 &\text{amp; } 9 \\ 1 &\text{amp; } 4\end{vmatrix} $ then $\text{A}=$
- ✓$\displaystyle \begin{vmatrix} 2 & 7 \\ 0 & 1\end{vmatrix} $
- B$\displaystyle \begin{vmatrix} 0 & 1 \\ 2 & 7\end{vmatrix} $
- C$\displaystyle \begin{vmatrix} 1 & 0 \\ 2 & 7\end{vmatrix} $
- D$\displaystyle \begin{vmatrix} 2 & 1 \\ 0 & 7\end{vmatrix} $