MCQ
If $\frac{\text{dy}}{\text{dx}}=\text{y}\sin2\text{x},\text{y}(0)=1$ then solution is:
  • $\text{y}=\text{e}\sin^2\text{x}$
  • B
    $\text{y}=\sin^2\text{x}$
  • C
    $\text{y}=\cos^2\text{x}$
  • D
    $\text{y}=\text{e}\cos^2\text{x}$

Answer

Correct option: A.
$\text{y}=\text{e}\sin^2\text{x}$

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