MCQ
If $\text{f(x)}=\frac{\sin^{4}\text{x}+\cos^2\text{x}}{\sin^2\text{x}+\cos^4\text{x}}$ for $\text{x}\in\text{R},$ then f(2002) =
  • 1
  • B
    2
  • C
    3
  • D
    4

Answer

Correct option: A.
1
Given,
$\text{f(x)}=\frac{\sin^{4}\text{x}+\cos^2\text{x}}{\sin^2\text{x}+\cos^4\text{x}}$
On dividing the numerator and denominator by $\cos^4\text{x},$ we get
$\text{f(x)}=\frac{\tan^4\text{x}+\sec^2\text{x}}{1+\tan^2\text{x}\sec^2\text{x}}$
$=\frac{1+\tan^4\text{x}+\tan^2\text{x}}{1+\tan^2\text{x}(1+\tan^2\text{x})}$
$=\frac{1+\tan^{4}\text{x}+\tan^{2}\text{x}}{1+\tan^{4}\text{x}+\tan^{2}\text{x}}=1$ $(\text{For every x}\in\text{R})$
$\text{For x}=2002,$
We have,
$\text{f}(2002)=1$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If P, Q and R are subsets of set A, then $\text{R }\times(\text{p}^\text{c} \cup\text{Q}^{\text{c}})^\text{c}=$
The centre of the circle passing through the point $(0,1)$ and touching the parabola $y=x^{2}$ at the point $(2,4)$ is
Consider the set $A=\{1,2,3, \ldots, 30\}$. The number of ways in which one can choose three distinct number from $A$ so that the product of the chosen numbers is divisible by $9$ is
Consider the experiment of rolling a die. Let $A$ be the event 'getting a prime number ', $B$ be the event 'getting an odd number '. Write the sets representing the events $A$ but not $B$
In a club election the number of contestants is one more than the number of maximum candidates for which a voter can vote. If the total number of ways in which a voter can vote be $62,$ then the number of candidates is :-
If $\tan\text{px}-\tan\text{qx}=0,$ then the values of $\theta$ form a series in:
Choose the correct answer. If the sum of $n$ terms of an A.P. is given by $S_n=3 n+2 n^2$, then the common difference of the A.P. is:
If ${(1 + x)^n} = {C_0} + {C_1}x + {C_2}{x^2} + ... + {C_n}{x^n}$, then the value of ${C_0} + {C_2} + {C_4} + {C_6} + .....$ is
In a high school, a committee has to be formed from a group of $6$ boys $M _1, M _2, M _3, M _4, M _5, M _6$ and $5$ girls $G _1, G _2, G _3, G _4, G _5$

$(i)$ Let $\alpha_1$ be the total number of ways in which the committee can be formed such that the committee has $5$ members, having exactly $3$ boys and $2$ girls.

$(ii)$ Let $\alpha_2$ be the total number of ways in which the committee can be formed such that the committee has at least $2$ members, and having an equal number of boys and girls.

$(iii)$ Let $\alpha_3$ be the total number of ways in which the committee can be formed such that the committee has $5$ members, at least $2$ of them being girls.

$(iv)$ Let $\alpha_4$ be the total number of ways in which the committee can be formed such that the committee has $4$ members, having at least $2$ girls and such that both $M _1$ and $G _1$ are $NOT$ in the committee together.

 $LIST I $ $LIST I $
$P$ The value of $\alpha_1$ is $1$ $136$
$Q$ The value of $\alpha_2$ is $2$ $189$
$R$ The value of $\alpha_3$ is $3$ $192$
$S$ The value of $\alpha_4$ is $4$ $200$
  $5$ $381$
  $6$ $461$

The correct option is:

Consider the following parametric equation of a curve $ x(\theta)=|\cos 4 \theta| \cos \theta $ ; $ y(\theta)=|\cos 4 \theta| \sin \theta $ ; $ 0 \leq \theta \leq 2 \pi $ Which one of the following graphs represents the curve?