Question
If $\text{n}\in\text{N},$ then find the value of $\text{i}^\text{n}+\text{i}^{\text{n}+1}+\text{i}^{\text{n}+2}+\text{i}^{\text{n}+3}.$

Answer

$\text{i}^\text{n}+\text{i}^{\text{n}+1}+\text{i}^{\text{n}+2}+\text{i}^{\text{n}+3}$ $=\text{i}^\text{n}+\text{i}^{\text{n}}.\text{i}+\text{i}^{\text{n}}.\text{i}^2+\text{i}^{\text{n}}.\text{i}^3$ $=\text{i}^\text{n}+\text{i}^{\text{n}}.\text{i}+\text{i}^{\text{n}}.(-1)+\text{i}^{\text{n}}.(-\text{i})$ $=\text{i}^\text{n}+\text{i}^{\text{n}}.\text{i}-\text{i}^{\text{n}}-\text{i}^{\text{n}}.\text{i}$ $=0$ Thus, the value of $\text{i}^\text{n}+\text{i}^{\text{n}+1}+\text{i}^{\text{n}+2}+\text{i}^{\text{n}+3}$ is 0.

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