Question
If ${^\text{n}}\text{C}_{12}={^\text{n}}\text{C}_{5},$ Find the value of n.

Answer

We have, ${ }^n C_r=\frac{n!}{r!(n-r)!}$ Hence, $n=m r=12$ and 5 Applying formula ${ }^n C_p={ }^n C_q=n$ Then $p+q=n={ }^n C_{12}={ }^n C_5 12$ $+5=n \Rightarrow n=17$

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