MCQ
If $\frac{\text{x}}{3}+\frac{1}{3}=1,$ then $x = ?$
- A$\frac{3}{4}$
- ✓$\frac{4}{3}$
- C$-\frac{3}{4}$
- D$\frac{-4}{3}$
✓
Answer
Correct option: B.
$\frac{4}{3}$
$\frac{\text{x}}{2}+\frac{1}{3}=1$
$\Rightarrow\frac{\text{x}}{2}=1-\frac{1}{3}$
$\Rightarrow\frac{\text{x}}{2}=\frac{3\times1-1}{3}$
$\Rightarrow\frac{\text{x}}{2}=\frac{3-1}{3}$
$\Rightarrow\frac{\text{x}}{2}=\frac{2}{3}$
$\Rightarrow\frac{2\text{x}}{2}=\frac{2\times2}{3}$ (Multiplying both sides by $2)$
$\Rightarrow\text{x}=\frac{4}{3}$
Hence, the correct answer is option $(b).$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In Figure. $\angle\text{BAC}=90^{\circ},$ $\text{AD}\bot\text{BC}$ and$\angle\text{ BAD}=50^{\circ},$ then$\angle\text{ ACD}$ is:
→Division of $9.826$ by $10$ gives:
→Find the angle, which is $60^\circ $ more than its complement.
→If $\frac{\text{x}}{3}+\frac{1}{3}=1,$ then $x = ?$
→The number of triangular faces of a triangular prism is _______.
In standard form, the number 829030000 is written as $k \times 10^8$, where $k$ is equal to
→Mark against the correct answer in the following:
The ages of $A$ and $B$ are in the ratio $3 : 8$. Six years hence, their ages will be in the ratio $4 : 9$. The present age of $A$ is:
→The ages of $A$ and $B$ are in the ratio $3 : 8$. Six years hence, their ages will be in the ratio $4 : 9$. The present age of $A$ is:
The range of observations $2, 3, 5, 9, 8, 7, 6, 5, 7, 4, 3$ is:
→Which of the following statements is true?
The product $\frac{3}{5} \times \frac{11}{17}$
→