MCQ
If $\text{x}=\text{a}\sec\theta \text{ and y}=\text{b}\tan\theta,$ then $b^2x^2 - a^2y^2 $=
- A$ab$
- B$a^2 - b^2$
- C$a^2 + b^2$
- ✓$a^2b^2$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| Varible $(x)$ | $1$ | $2$ | $3$ | $4$ | $5$ |
| Fraquency | $4$ | $5$ | $y$ | $1$ | $2$ |