Question
If $\text{x}=\text{t}^2$ and $\text{y}=\text{t}^3$ then find $\frac{\text{d}^2\text{y}}{\text{dx}^2}$
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Question is modified
If $|\mathrm{x}|<1$, then prove that $2 \tan ^{-1} \mathrm{x}=\tan ^{-1}\left(\frac{2 x}{1-x^2}\right)=\sin ^{-1}\left(\frac{2 x}{1+x^2}\right)=\cos ^{-1}\left(\frac{1-x^2}{1+x^2}\right)$
$\cos ^7 x$