MCQ
If $\text{x}=\text{t}^2,\text{y}=\text{t}^3$ Then $\frac{\text{d}^2\text{y}}{\text{dx}^2}=$
- A$\frac{3}{2}$
- B$\frac{3}{4\text{t}}$
- C$\frac{3}{2\text{t}}$
- ✓$\frac{3\text{t}}{2}$
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