MCQ
If $\text{x}:\text{y}=1:1,$ then $\frac{3\text{x}+4\text{y}}{5\text{x}+6\text{y}}=$
- ✓$\frac7{11}$
- B$\frac{17}{11}$
- C$\frac{17}{23}$
- D$\frac45$
As, $\text{x}:\text{y}=1:1$
$\Rightarrow\frac{\text{x}}{\text{y}}=\frac{1}{1}$
$\Rightarrow\text{x}=\text{y}$
Now,
$\frac{\text{3x}+4\text{y}}{5\text{x}+6\text{y}}$
$=\frac{3\text{x}+4\text{x}}{5\text{x}+6\text{x}} (As, x = y)$
$=\frac{7\text{x}}{11\text{x}}$
$=\frac{7}{11}$
Hence, the correct alternative is option $(a).$
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