If (x+y)^2 dy dx =a^2,y=0 when x = 0, then y = a if x a = - Vidyadip

MCQ

If $(\text{x}+\text{y})^2\frac{\text{dy}}{\text{dx}}=\text{a}^2,\text{y}=0$ when $x = 0,$ then $y = a$ if $\frac{\text{x}}{\text{a}}=$

A
$1$
B
$\tan1$
C
$\tan1+1$
✓
$\tan1-1$

✓

Answer

Correct option: D.

$\tan1-1$

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