MCQ
If $\text{y}=\text{a}+\text{bx}^2,\text{a,b}$ arbitrary constants, then
- A$\frac{\text{d}^2\text{y}}{\text{dx}^2}=2\text{xy}$
- ✓$\text{x}\frac{\text{d}^2\text{y}}{\text{dx}^2}=\text{y}_1$
- C$\text{x}\frac{\text{d}^2\text{y}}{\text{dx}^2}-\frac{\text{dy}}{\text{dx}}+\text{y}=0$
- D$\text{x}\frac{\text{d}^2\text{y}}{\text{dx}^2}=2\text{xy}$