MCQ
If the capacitors in the previous question are joined in parallel, the capacitance and the breakdown voltage of the combination will be :
- A$2C$ and $2V$
- B$C$ and $2V$
- ✓$2C$ and $V$
- D$C$ and $V$
✓
Answer
Correct option: C.
$2C$ and $V$
In a parallel combination of capacitors, the potential difference across the capacitors remain the same, as the right $-$ hand $-$ side plates and the left $-$ hand $-$ side plates of both the capacitors are connected to the same terminals of the battery.
Therefore, the potential remains the same, that is, $V$.
For the parallel combination of capacitors, the capacitance is given by
$C_{e q}=C_1+C_2$
Here $, C_1=C_2=C $
$\therefore C_{\text {eq }}=2 C$
Therefore, the potential remains the same, that is, $V$.
For the parallel combination of capacitors, the capacitance is given by
$C_{e q}=C_1+C_2$
Here $, C_1=C_2=C $
$\therefore C_{\text {eq }}=2 C$
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