If the circle x^2+ y^2= 9 passesthrough (2, c) then c is equal to… - Vidyadip

MCQ

If the circle $x^2+ y^2= 9$ passesthrough $(2, c)$ then $c$ is equal to:

✓
$\sqrt{5}$
B
$\sqrt{6}$
C
$\sqrt{3}$
D
$\sqrt{7}$

✓

Answer

Correct option: A.

$\sqrt{5}$

The equation of circle $x^2+y^2=9$ The point is $(2, c)$
$ \Rightarrow 2^2+c^2=9 $
$ 4+c^2=9 $
$ c^2=9-4 $
$ c^2=5 $
$\text{c}=\sqrt{5}$

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