If the circle x^2+ y^2= 9 passesthrough (2, c) then cc is equal t… - Vidyadip

MCQ

If the circle $x^2+ y^2= 9$ passesthrough $(2, c)$ then $cc$ is equal to:

✓
$\sqrt5$
B
$\sqrt 6$
C
$\sqrt 3$
D
$\sqrt 7$

✓

Answer

Correct option: A.

$\sqrt5$

The equation of circle $x^2+ y^2= 9$ The point is $(2,c)$
$\Rightarrow 2^2+ c^2= 94 + c^2= 9$
$c^2= 9 - 4$
$c^2= 5$
$\text{c}=\sqrt{5}$

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