If the constraints in a linear programming problem are changed 1.… - Vidyadip

Question

If the constraints in a linear programming problem are changed

the problem is to be re-evaluated
solution is not defined
the objective function has to be modified
the change in constraints is ignored

✓

Answer

the problem is to be re-evaluated

Solution:

The optimisation of the objective function of a LPP is governed by the constraints.

Therefore, if the constraints in a linear programming problem are changed, then the problem needs to be re-evaluated.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Linear programming→Linear programming — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

Let X be a discrete random variable. Then the variance of X is:

E(X²)
E(X²) + (E(X))²
E(X²) - (E(X))²
$\sqrt{\text{E}(\text{X}^2)-(\text{E}(\text{X}))^2}$

Let $f: R \rightarrow R$ be defined as $f( x )=2 x -1$ and $g: R-\{1\} \rightarrow R$ be defined as $g(x)=\frac{x-\frac{1}{2}}{x-1}$ Then the composition function $f(g(x))$ is

The elimination of the arbitrary constants $A, B$ and $C$ from $y = A + Bx + C{e^{ - x}}$leads to the differential equation

$\int {\frac{{\cos x + x\sin x}}{{x(x - \cos x)}}dx = } $

$\int_{}^{} {\frac{{\sin x\;dx}}{{{{(a + b\cos x)}^2}}} = } $

$\int_{\,1}^{\,3} {(x - 1)(x - 2)(x - 3)dx = } $

If $\tan^{-1}3+\tan^{-1}\text{x}=\tan^{-1}8,$ then x =

$5$
$\frac{1}{5}$
$\frac{5}{14}$
$\frac{14}{5}$

A bag containe 5 black, 4white balls and 3 red balls. if a ball is selected randomwise, the probability that it is black or red ball is,

$\frac{1}{3}$
$\frac{1}{4}$
$\frac{5}{12}$
$\frac{2}{3}$

A person writes 4 letters and addresses 4 envelopes. If the letters are placed in the envelopes at random, then the probability that all letters are not placed in the right envelopes, is

$\frac{1}{4}$
$\frac{11}{14}$
$\frac{15}{24}$
$\frac{23}{24}$

Choose the correct option from given four options:
If $\int\frac{\text{dx}}{(\text{x}+2)(\text{x}^2+1)}=\text{a}\log|1+\text{x}^2|+\text{b}\tan^{-1}\text{x}+\frac{1}{5}\log|\text{x}+2|+\text{C},$ then:

$\text{a}=\frac{-1}{10},\text{b}=\frac{-2}{5}$
$\text{a}=\frac{-1}{10},\text{b}=-\frac{2}{5}$
$\text{a}=\frac{-1}{10},\text{b}=\frac{2}{5}$
$\text{a}=\frac{1}{10},\text{b}=\frac{2}{5}$