MCQ
If the circles ${x^2} + {y^2} = 4,{x^2} + {y^2} - 10x + \lambda = 0$ touch externally, then $\lambda $ is equal to
- ✓$-16$
- B$9$
- C$16$
- D$25$
${C_1}{C_2} = {r_1} + {r_2}$
==> ${C_1}(0,\,0)$ and ${C_2} = (5,\,0)$
${r_1} = 2$ and ${r_2} = \sqrt {25 + \lambda } $
$\sqrt {{{(5 - 0)}^2} + 0} = 2 + \sqrt {25 + \lambda } $
==> $5 - 2 = \sqrt {25 + \lambda } $
==> $3 = \sqrt {25 + \lambda } $
==> $9 = 25 + \lambda $
==> $\lambda$ $= -16.$
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$(A)$ $\left(\frac{9}{2 \sqrt{2}}, \frac{1}{\sqrt{2}}\right)$ $(B)$ $\left(-\frac{9}{2 \sqrt{2}},-\frac{1}{\sqrt{2}}\right)$
$(C)$ $(3 \sqrt{3},-2 \sqrt{2})$ $(D)$ $(-3 \sqrt{3}, 2 \sqrt{2})$