MCQ
If the difference between the roots of the equation $x^2 + ax + b = 0$ is equal to the difference between the roots of the equation $x^2 + bx + a = 0 (a \ne b)$ , then
- A$a + b = 4$
- ✓$a + b = -4$
- C$a -b = 4$
- D$a -b = -4$
$(\alpha+\beta)^{2}-4 \alpha \beta=\left(\alpha^{\prime}+\beta^{\prime}\right)^{2}-4 \alpha^{\prime} \beta^{\prime}$
$\Rightarrow a^{2}-4 b=b^{2}-4 a$
${a^{2}-b^{2}=4(b-a)} $
${(a-b)(a+b)=-4(a-b)}$
$\Rightarrow(a+b)=-4$
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