MCQ
If the difference of two complementary angles is $10^\circ ,$ then the smaller angle is
  • $40^{\circ}$
  • B
    $50^{\circ}$
  • C
    $45^{\circ}$
  • D
    $35^{\circ}$

Answer

Correct option: A.
$40^{\circ}$
Let first angle $= x$
Then its complementary angle $=90^{\circ}-x$
Now $x-\left(90^{\circ}-x\right)=10^{\circ}$
$\Rightarrow x-90^{\circ}+x=10^{\circ}$
$\Rightarrow 2 x=10^{\circ}+90^{\circ}=100^{\circ}$
$\Rightarrow x=50^{\circ}$
Second angle $=90^{\circ}-50^{\circ}=40^{\circ}$
Smaller angle $=40^{\circ}$

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