MCQ
If the dimensions of a physical quantity are given by $M^aL^bT^c$ ,then physical quantity will be
- Avelocity if $a=1,b=0,c=-1$
- Bacceleration if $a=1,b=1,c=-2$
- Cforce if $a=0,b=-1,c=-2$
- ✓pressure if $a=1,b=-1,c=-2$
✓
Answer
Correct option: D.
pressure if $a=1,b=-1,c=-2$
d
Pressure, $p = \frac{{force}}{{area}} = \frac{{mass\, \times \,acceleration}}{{area}}$
$\therefore \,\left[ P \right] = \frac{{{M^1}L{T^{ - 2}}}}{{{L^2}}} = \left[ {{M^1}{L^{ - 1}}{T^{ - 2}}} \right] = \,{M^a}{L^b}{T^c}$
$\therefore \,a = 1,\,b = - 1,\,c = - 2.$
Pressure, $p = \frac{{force}}{{area}} = \frac{{mass\, \times \,acceleration}}{{area}}$
$\therefore \,\left[ P \right] = \frac{{{M^1}L{T^{ - 2}}}}{{{L^2}}} = \left[ {{M^1}{L^{ - 1}}{T^{ - 2}}} \right] = \,{M^a}{L^b}{T^c}$
$\therefore \,a = 1,\,b = - 1,\,c = - 2.$
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