If the displacement of a particle executing $SHM $ is given by $y = 0.30\sin (220t + 0.64)$ in metre, then the frequency and maximum velocity of the particle is
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(a) $n = \frac{\omega }{{2\pi }} = \frac{{220}}{{2\pi }} = 35\,Hz$
${v_{\max }} = \omega \,a = 220 \times 0.30\,m/s = 66\,m/s$
${v_{\max }} = \omega \,a = 220 \times 0.30\,m/s = 66\,m/s$
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