Answer

Correct option: D.
(d) $\frac{1}{4}$times
Explaination : $
F_g=G \frac{m_1 m_2}{r^2}
$
Therefore, $F _{ g } \propto \frac{1}{ r ^2}$
Hence, if the distance between the bodies is doubled, the gravitational force of attraction becomes one-fourth.

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