MCQ
If the distance between two masses be doubled, then the force between will become:
  • $\frac{1}{4}$times
  • B
    4 times
  • C
    $\frac{1}{2}$times
  • D
    2 times

Answer

Correct option: A.
$\frac{1}{4}$times
(a) $\frac{1}{4}$times
Explaination : $
F_g=G \frac{m_1 m_2}{r^2}
$
Therefore, $F _{ g } \propto \frac{1}{ r ^2}$
Hence, if the distance between the bodies is doubled, the gravitational force of attraction becomes one-fourth.

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