If the equation of transverse wave is $y = 5\sin 2\pi \left[ {\frac{t}{{0.04}} - \frac{x}{{40}}} \right]$, where distance is in $ cm$ and time in second, then the wavelength of the wave is .... $cm$
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(b) Comparing with $y = a\sin 2\pi \left[ {\frac{t}{T} - \frac{x}{\lambda }} \right]$==> $\lambda = 40\,cm$
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