MCQ
If the equation ${x^2} + \lambda x + \mu = 0$ has equal roots and one root of the equation ${x^2} + \lambda x - 12 = 0$ is $2$, then $(\lambda ,\mu )=$
- ✓$(4, 4)$
- B$(-4,4)$
- C$(4, - 4)$
- D$( - 4, - 4)$
Now second equation ${x^2} + \lambda x - 12 = 0$ has a root $2$,
so put $x = 2$==> $4 + 2\lambda - 12 = 0$==> $\lambda = 4$
Hence from ${\lambda ^2} = 4\mu $, we have $\mu = \frac{{16}}{4} = 4$
==> $(\lambda ,\mu ) = (4,4)$.
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