MCQ
If the events $A$ and $B$ are mutually exclusive, then $P\left( {\frac{A}{B}} \right) = $
  • $0$
  • B
    $1$
  • C
    $\frac{{P\,(A \cap B)}}{{P\,(A)}}$
  • D
    $\frac{{P\,(A \cap B)}}{{P\,(B)}}$

Answer

Correct option: A.
$0$
a
(a) $P\left( {\frac{A}{B}} \right) = \frac{{P(A \cap B)}}{{P(B)}}$

Since $A$ and $B$ are mutually exclusive.

So, $P(A \cap B) = 0$.

Hence $P\left( {\frac{A}{B}} \right) = \frac{0}{{P(B)}} = 0$.

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