MCQ
If the events $A$ and $B$ are mutually exclusive, then $P\left( {\frac{A}{B}} \right) = $
- ✓$0$
- B$1$
- C$\frac{{P\,(A \cap B)}}{{P\,(A)}}$
- D$\frac{{P\,(A \cap B)}}{{P\,(B)}}$
Since $A$ and $B$ are mutually exclusive.
So, $P(A \cap B) = 0$.
Hence $P\left( {\frac{A}{B}} \right) = \frac{0}{{P(B)}} = 0$.
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