Question
If the function $\text{f(x)}=\frac{2\text{x}-\sin^{-1}\text{x}}{2\text{x}+\tan^{-1}\text{x}}$ is continuous at each point of its domain, then the value of f(0) is:
  1. $2$
  2. $\frac{1}{3}$
  3. $-\frac{1}{3}$
  4. $\frac{2}{3}$

Answer

  1. $\frac{1}{3}$
Solution:
$\text{f}(0)=\lim\limits_{\text{x}\rightarrow0}\frac{2\times-\sin^{-1}\text{x}}{2\times+\tan^{-1}\text{x}}$
$\text{f}\text{(0)}=\lim\limits_{\text{x}\rightarrow0}\frac{2\times-\frac{\sin^{-1}\text{x}}{\text{x}}}{2+\frac{\tan^{-1}\text{x}}{\text{x}}}$
$\text{f}(0)=\frac{2-1}{2+1}=\frac{1}{3}$

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