Question
If the function $\text{f(x)}=\frac{2\text{x}-\sin^{-1}\text{x}}{2\text{x}+\tan^{-1}\text{x}}$ is continuous at each point of its domain, then the value of f(0) is:
  1. $2$
  2. $\frac{1}{3}$
  3. $-\frac{1}{3}$
  4. $\frac{2}{3}$

Answer

  1. $\frac{1}{3}$

Solution:

$\text{f}(0)=\lim\limits_{\text{x}\rightarrow0}\frac{2\times-\sin^{-1}\text{x}}{2\times+\tan^{-1}\text{x}}$

$\text{f}\text{(0)}=\lim\limits_{\text{x}\rightarrow0}\frac{2\times-\frac{\sin^{-1}\text{x}}{\text{x}}}{2+\frac{\tan^{-1}\text{x}}{\text{x}}}$

$\text{f}(0)=\frac{2-1}{2+1}=\frac{1}{3}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Q+ is the set of all positive rational numbers with the binary operation * defined by $\text{a}*\text{b}=\frac{\text{ab}}2\ \forall\text{ a, b}\in\text{Q}^+$. The inverse of an element $\text{a}\in\text{Q}^+$ is:
  1. $\text{a}$
  2. $\frac{1}{\text{a}}$
  3. $\frac{2}{\text{a}}$
  4. $\frac{4}{\text{a}}$
$\int {\frac{{dx}}{{7 + 5\cos x}} = } $
A flash light has 8 batteries out of which 3 are dead. IF two batteries are selected without replacement and tested, then the probability that both are dead is,
  1. $\frac{3}{28}$
  2. $\frac{1}{14}$
  3. $\frac{9}{64}$
  4. $\frac{33}{56}$
The area of the region bounded by $y=|| x-3|-4|-5$ and the $X$-axis is
The maximum value of the function $f(x)=e^x+x \ln x$ on the interval $1 \leq x \leq 2$ is
The eqution of the plane contaning the two lines $\frac{\text{x}-1}{2}=\frac{\text{y}+1}{-1}=\frac{\text{z}-0}{3}$ and $\frac{\text{x}}{-2}=\frac{\text{y}-2}{-3}=\frac{\text{z}+1}{-1}$ is:
  1. 8x + y - 5z - 7 = 0
  2. 8x + y + 5z - 7 = 0
  3. 8x - y - 5z - 7 = 0
  4. None of these
The maximum slope of the curve $y=\frac{1}{2} x^{4}-5 x^{3}+18 x^{2}-19 x$ occurs at the point
Integrate the following functions with respect to x: $\int\frac{\text{dx}}{4\text{x}+5}$
  1. $\frac{1}{4}\text{ In }(4\text{x}+5)+\text{c}$
  2. $\frac{1}{4}\text{ In }(4\text{x}+5)-\text{c}$
  3. $\frac{-1}{4}\text{ In }(4\text{x}+5)-\text{c}$
  4. $4\text{ In }(4\text{x}-5)-\text{c}$
If $a = i - j + k,\,\,b = i + 2j - k$ and $c = 3i + pj + 5k$ are coplanar then the value of $p$ be
$\sin\Big\{2\cos^{-1}\Big(\frac{-3}{5}\Big)\Big\}$ is equal to:
  1. $\frac{6}{25}$
  2. $\frac{24}{25}$
  3. $\frac{4}{5}$
  4. $-\frac{24}{25}$