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RELATIONS AND FUNCTIONS — MATHS STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceMATHSRELATIONS AND FUNCTIONS2 Marks
Question
If the function t which maps temperature in degree Celcius into temperature in degree Fahrenheit is defined by t(C) = $\frac{9C}{5}$+ 32, then find t(28).
✓

Answer

We have, $t(C) =$ $\frac{9 C}{5}$$+ 32$
On putting C = 28, we get
$t(28) = $$\frac{9 \times 28}{5}$ $+ 32 =$ $\frac{252}{5}$ + $\frac{32}{1}$
= $\frac{252+160}{5}$ = $\frac{412}{5}$ = 82.4

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