Download App

2. structure of atom — Chemistry STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 ScienceChemistry2. structure of atom1 Mark
MCQ
If the $I.E.$ of $He^+$ us $54.4\,eV$ then -
  • ✓
    $I.E.$ of $H$ is $13.6\,eV$ and that of $Li^{+2}$ $122.4\,eV$
  • B
    $I.E.$ of $H$ is $13.6\,eV$ and that of $Li^{+2}$ cannot be determined
  • C
    $I.E.$ of $H$ is $13.6\,eV$ and that of $Li^{+2}$ is $27.2\,eV$
  • D
    All of the above are wrong
✓

Answer

Correct option: A.
$I.E.$ of $H$ is $13.6\,eV$ and that of $Li^{+2}$ $122.4\,eV$
a

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 2. structure of atom→2. structure of atom — all question types→Chemistry STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

Arrange the carbanions, ${\left( {C{H_3}} \right)_3}\bar C,\,\bar CC{l_3},\,{\left( {C{H_3}} \right)_2}\bar CH,\,{C_6}{H_5}\bar C{H_2}$ in order of their decreasing stability
→
Identify the correct sequence of increasing number of $\pi$-bonds in the structure of  the following molecules

$(I)\, H_2S_2O_6$           $(II)\, H_2S_2O_3$           $(III)\,H_2S_2O_5$ 

→
$10$ moles of an ideal gas confined to a volume of $10\,L$ is released into atmosphere at $300\, K$ where the pressure is $1\, bar.$ The work done by the gas is ....$L\, bar$

$(R = 0.083\, L\, bar\, K^{-1} \,mol^{-1})$

→
In presence of HCl(aq.);H2​S gas results the precipitation of group-2 cations but not of group-4 cations during qualitative analysis. It is due to:
→
Which of the following is the energy of a possible excited state of hydrogen?
→
Dichloro carbene form by chloroform and alc. $KOH$, which reaction involve this carbene
→
$\begin{array}{*{20}{c}}
  {C{H_2} - C{O_2}K} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_2} - C{O_2}K} 
\end{array}\xrightarrow{{electrolysis}}\mathop {(A)}\limits_{\left( {major} \right)} $ (Kolbe electrolysis method)

Product $(A)$ of the reaction is 

→
$STATEMENT-1:$ There is a natural asymmetry between converting work to heat and converting heat to work. and

$STATEMENT-2:$ No process is possible in which the sole result is the absorption of heat from a reservoir and its complete conversion into work.

→
Which of the following shows the correct order of decreasing acidity
→
Which of the following options does not represent ground state electronic configuration of an atom?
→