MCQ
If the ionization enthalpy and electron gain enthalpy of an element are $275$ and $86\, kcal\, mol^{-1}$ respectively, then the electronegativity of the element on the Pauling scale is
- ✓$2.8$
- B$0$
- C$4$
- D$2.6$
$\therefore$ Electroneganvity $= \frac{1510.42}{540} = 2.797 = 2.8$
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