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6.2. Equilibrium - II (icon Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.2. Equilibrium - II (icon Equilibrium)1 Mark
MCQ
If the ${K_b}$ value in the hydrolysis reaction ${B^ + } + {H_2}O$ $\rightleftharpoons$ $BOH + {H^ + }$ is $1.0 \times {10^{ - 6}},$ then the hydrolysis constant of the salt would be
  • A
    $1.0 \times {10^{ - 6}}$
  • B
    $1.0 \times {10^{ - 7}}$
  • ✓
    $1.0 \times {10^{ - 8}}$
  • D
    $1.0 \times {10^{ - 9}}$
✓

Answer

Correct option: C.
$1.0 \times {10^{ - 8}}$
(c) For hydrolysis of ${B^ + }$; ${K_H} = \frac{{{K_w}}}{{{K_b}}}$$ = \frac{{{{10}^{ - 14}}}}{{{{10}^{ - 6}}}} = {10^{ - 8}}$.

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