MCQ
If the length of a closed organ pipe is $1.5\, m$ and velocity of sound is $330 m/s$, then the frequency for the second note is ... $Hz$
- A$220 $
- ✓$165 $
- C$110 $
- D$55$
✓
Answer
Correct option: B.
$165 $
b
(b) For closed pipe second note
(b) For closed pipe second note
= $\frac{{3v}}{{4l}} = \frac{{3 \times 330}}{{4 \times 1.5}} = 165$ $Hz$.
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