If the matrix A= [ cc 3-2 x & x+1 2 & 4 ] is singular then x = ? - Vidyadip

Question

If the matrix $A=\left[\begin{array}{cc}3-2 x & x+1 \\ 2 & 4\end{array}\right]$ is singular then $x =$ ?

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Answer

$(a)\ 1$
Explanation : When a given matrix is singular then the given matrix determinant is $0$.
$|A|=0$
Given, $A=\left(\begin{array}{cc}3-2 x & x+1 \\ 2 & 4\end{array}\right)$
$|A|=0$
$4(3-2 x)-2(x+1)=0$
$12-8 x-2 x-2=0$
$10-10 x=0$
$10(1-x)=0$
$x=1$

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