MCQ
If the minimum and the maximum values of the function $f :\left[\frac{\pi}{4}, \frac{\pi}{2}\right] \rightarrow R ,$ defined by : 

$f (\theta)=\left|\begin{array}{ccc}-\sin ^{2} \theta & -1-\sin ^{2} \theta & 1 \\ -\cos ^{2} \theta & -1-\cos ^{2} \theta & 1 \\ 12 & 10 & -2\end{array}\right|$ are $m$ and $M$ respectively, then the ordered pair $( m , M )$ is equal to

  • A
    $(0,4)$
  • B
    $(-4,4)$
  • C
    $(0,2 \sqrt{2})$
  • $(-4,0)$

Answer

Correct option: D.
$(-4,0)$
d
$C _{3} \rightarrow C _{3}-\left( C _{1}- C _{2}\right)$

$f(\theta)=\left|\begin{array}{ccc}-\sin ^{2} \theta & -1-\sin ^{2} \theta & 0 \\ -\cos ^{2} \theta & -1-\cos ^{2} \theta & 0 \\ 12 & 10 & -4\end{array}\right|$

$=-4\left[\left(1+\cos ^{2} \theta\right) \sin ^{2} \theta-\cos ^{2} \theta\left(1+\sin ^{2} \theta\right)\right]$

$=-4\left[\sin ^{2} \theta+\sin ^{2} \theta \cos ^{2} \theta-\cos ^{2} \theta-\cos ^{2} \theta \sin ^{2} \theta\right]$

$f(\theta)=4 \cos 2 \theta$

$\theta \in\left[\frac{\pi}{4}, \frac{\pi}{2}\right]$

$2 \theta \in\left[\frac{\pi}{2}, \pi\right]$

$f(\theta) \in[-4,0]$

$( m , M )=(-4,0)$

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