If the n^ th term a_n of sequence is given by a_n=n^2-6n^2-n+1, write down its first five terms.

a_n=n^2-n+1 is the given sequencethen, first 5 tems are a_1, a_2, a_3, a_4 and a_5 a_1=(1)^2-1+1=1 a_2=(2)^2-2+1=3 a_2=(3)^2-3+1=7 a^4=(4)^2-4+1=13 a_5=(5)^2-5+1=21First 5 terms 1, 3, 7, 13 and 21,

If the n^ th term a_n of sequence is given by a_n=n^2-6n^2-n+1, w…

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If the $n^{th}$ term $a_n$ of sequence is given by $\text{a}_\text{n}=\text{n}^2-6\text{n}^2-\text{n}+1,$ write down its first five terms.

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Answer

$\text{a}_\text{n}=\text{n}^2-\text{n}+1$ is the given sequencethen, first 5 tems are $\text{a}_1,\ \text{a}_2,\ \text{a}_3,\ \text{a}_4$ and $\text{a}_5$
$\text{a}_1=(1)^2-1+1=1$ $\text{a}_2=(2)^2-2+1=3$ $\text{a}_2=(3)^2-3+1=7$ $\text{a}^4=(4)^2-4+1=13$ $\text{a}_5=(5)^2-5+1=21$First 5 terms $1, 3, 7, 13$ and $21$,

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