MCQ
If the numbers $a,\;b,\;c,\;d,\;e$ form an $A.P.$, then the value of $a - 4b + 6c - 4d + e$ is
  • A
    $1$
  • B
    $2$
  • $0$
  • D
    None of these

Answer

Correct option: C.
$0$
c
(c) Let $D$ be the common difference of the $A.P.$

Then, $a - 4b + 6c - 4d + e  $

$=a - 4(a + D) + 6(a + 2D) - 4(a + 3D) + (a + 4D) = 0$.

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