MCQ
If the numbers $a,\;b,\;c,\;d,\;e$ form an $A.P.$, then the value of $a - 4b + 6c - 4d + e$ is
- A$1$
- B$2$
- ✓$0$
- DNone of these
Then, $a - 4b + 6c - 4d + e $
$=a - 4(a + D) + 6(a + 2D) - 4(a + 3D) + (a + 4D) = 0$.
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