MCQ
If the $pH$ of a solution is $4.0 $ at ${25\,^o}C,$ its $pOH$ would be $({K_w} = {10^{ - 14}})$
- A$4$
- B$6$
- C$8$
- ✓$10$
$pOH = 14 - pH$ ; $pOH = 14 - 4.0 = 10.0$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$O _{2}^{+}, O _{2}, O _{2}^{-}, O _{2}^{2-}$
For increasing bond order the correct option is ..... .
