MCQ
If the points $(a,\,0),\;(0,\,b)$ and $(1, 1)$ are collinear, then
- A$\frac{1}{{{a^2}}} + \frac{1}{{{b^2}}} = 1$
- B$\frac{1}{{{a^2}}} - \frac{1}{{{b^2}}} = 1$
- ✓$\frac{1}{a} + \frac{1}{b} = 1$
- D$\frac{1}{a} - \frac{1}{b} = 1$
$\Rightarrow \,\,a\,(b - 1) + 0 + 1\,( - b) = 0$
$ \Rightarrow \,\,ab - a - b = 0\,\,\,$
$\Rightarrow \,\,\frac{1}{a} + \frac{1}{b} = 1$.
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