MCQ
If the potential difference between the ends of a fixed resistor is halved, the electric power will become:
- ADouble.
- BHalf.
- CFour times.
- DOne-fourth.
✓
Answer
- One-fourth.
Explanation:
Since $\text{P}=\frac{\text{V}^2}{\text{R}}, $ when the potential difference is halved, the power becomes one-fourth.
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